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[QUOTE]Originally posted by Identity Crisis: [QB] "You wouldn't let it lie..." Momentum is conserved at every step. Momentum is a vector quantity not a scalar one. You have to add it according to vector rules. But even according to your simplistic system of scalar addition the momentum is conserved. 2[mv] goes into the system (mv for the ship and -mv for the ship, both in the x-axis) and 2[mv] comes out of the system (-mv for the ship and mv for the particle, but now both in the y-axis). No extra momentum is being created at any stage other than when the particle is first created in the reactor. The only scalar quantity available to us is kinetic energy. Can you give any step in the first (perfectly elastic) process where the KE of the particle is not the same as in all other steps? No, it is always 1/2 m v^2 because the speed of the particle is always [v] (the velocity changed with every step because the direction changes, but the speed stays the same). [/QB][/QUOTE]
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