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What's the density of stored antimatter?
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[QUOTE]Originally posted by fructose1: [QB] What you need to do is find the density of liquid hydrogen. Fluids are very difficult to compress, so the density of liquid hydrogen would be about the same at any pressure, assuming 1 atm. And (anti)deuteriun has an atomic mass of 2 since it's got a (anti-)proton and a (anti-)neutron. Just double the density since you now have twice the mass. Take that info, and the fact that the density of solid deuterium would be slightly higher than the liquid since most liquids are slightly less dense than their solids. (Water being a notable exception.) Also, when a solid melts, it will stay at it's melting point until it is completely liquid. So, increase the density of deuterium ever so slightly and you'll probably have a pretty close number to what it's density would be. Some sice notes: According to my research, hydrogen melts at 14 K, and since deuteruim is heavier, I would assume it's melting point is a little different. So 13.8 K sounds right. Also, the ideal gas law is pretty much worthless in this temp range. You would need the van der Waals equation: (p + (n^2a/V^2))(V - nb) = nRT If you want to get more info on this, go to [URL=http://www.chem.ualberta.ca/~plambeck/che/struct/s0307.htm]http://www.chem.ualberta.ca/~plambeck/che/struct/s0307.htm[/URL] , and [URL=http://www.chemicalelements.com/elements/h.html]http://www.chemicalelements.com/elements/h.html[/URL] . [/QB][/QUOTE]
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